Chemistry- how to turn a solid into a liquid amount?

Question

We are making dulutions of 200 mL, so how would we get
4M NaOH (solid) into a liquid by doing stociometrey.

So basically- how would you be able to go from moles of a solid into a liquid amount of a solid- when this is the only infromation given.

We also got this equation. (Mcon * mL con= Mdil * mL Dil) but I dont think this equation is useful for this problem.

Please help. I need this by tomorrow!

Answer 1

You, apparently, already have it in a ‘liquid’ form…you just don’t realize it.

“4M NaOH”,
Means that you have a SOLUTION of Sodium Hydroxide that has a concentration of 4 Moles of NaOH per Liter of solution (4 Molar).
We assume the solution to be of Sodium Hydroxide and water….so it is already in a liquid form.

Molarity = moles of solute / Liters of solution

The equation you have that reads,
“Mcon * mL con= Mdil * mL Dil”
Refers to the fact that where you dilute a solution, you are not changing the number of moles of solute, only the volume, so the total moles dissolved remains constant.


Multiplying the concentration (in terms of Molarity) by the volume gives you the total number of moles.
Mcon * mL con means to multiply the concentrated concentration by the volume of the solution to get the number of moles of solute in that, concentrated, solution. This is equal to the number of moles in the dilute solution which is given by the product of the dilute solution’s concentration multiplied by its volume.

For example, lets say you dissolved 2 moles of NaOH in enough water to make the solution’s final volume to be 1 Liter (= 1000 mL).
Molarity = moles / Liters
So your Molar concentration would be 2 Molar (2 M).

If you wanted to dilute this solution to a final concentration of 1 molar, you can use you formula this way,
(2 M) * (1 Liter) = (1 M) * V_final
Where V_final is the final volume of the solution of concentration 1 Molar when it started out as a 2 Molar, 1 Liter solution.
Solving for V_final, we find that one would need to dilute the solution to a final volume of 2 Liters to reduce its concentration down to 1 Molar.
In this process, you did not change the number of moles of NaOH, you just changed the amount of water it was dissolved in.

Answer 2

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