data results for trial 1 are, (mass of salt+evaporating dish) is 42.5054g an a average Mass of evaporating dish(empty) at 42.4519g with a Mass salt of 0.0535g. The second trial being (mass of salt+evaporating dish) is 42.5924g an a average Mass of evaporating dish(empty) at 42.5807g and a Mass of salt at 0.0117.
(i am ask to calculate the Ksp)but i dont know how, can someone please explain, thanks in advance
2007-03-13 16:56:35 · 2 answers · asked by omar d 1 in Science & Mathematics ➔ Chemistry
i am ask to give the calculation of these two trials, she gave me the Ksp's but i dont undertsand why
2007-03-13 17:16:02 · update #1
yes, the first trial pertains to CaSO4 and the second trial to BaSO4, the chart ask me 2 give the molar solubility of the salt of these two trials and the Ksp for salt
2007-03-13 17:20:06 · update #2
Without going into the math, trial 1 appears to be for CaSO4 and trial 2 for BaSO4. For CaSO4, we can determine, from the given salt mass, the moles corrresponding to a mole-weight of 136 for CaSO4 [0.0535/136]. From the Ksp and the atomic weight of the constiutents, we can work back to the initial liquid volume in the sample.
[0.0535/136V]^2= 2.4x10^-5
For trial 2, we can again find the mass of each ion in the salt, find the molar concentrations (assuming the liquid volume for each trial was the same), and compute Ksp for BaSO4.
2007-03-13 17:13:01 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋
there is something wrong with your question. since you have the Ksp value of BaSO4, why ask the same?
2007-03-13 17:04:14 · answer #2 · answered by kasaru_v4 1 · 0⤊ 0⤋