Can someone please divide and simplify the following problem:?

Question

20x to the power of 6 over 5y to the power of 9 divided by 16x to the power of 2 over 10 y to the power of 5. I'm trying to solve this problem ever since I got home from school and the answer I keep on getting does not match up with the answer on the back of my textbook. I'm so frustrated

Answer 1

I did this a few years ago so it's not so fresh in my mind. But I believe the answer is 5X to the fourth over 2Y to the fourth. Or the way that you state it would be 5X to the power of four over 2Y to the power of four. Is that what the book said?

Answer 2

ok as i see it the problem is

( (20x^6 / (5y^9 ) / ( (16x^2 / (10y^5 )
ok well when you divide by fractions, you multiply the first friction by the reciprocal of the second fraction

so it now reads
( (20x^6 / (5y^9 ) * ( (10y^5 / (16x^2 )

so lets combine numerators and denominators

( 20x^6 * 10y^5 ) / ( 5y^9 * 16x^2)
200x^6y^5 / 80x^2y^9
(200/80 reduces to 5/2)
5x^6y^5 / 2x^2y^9
so to bring up the x and y in the denominator when you bring them to the numerator the exponents values become opposite signs
5x^6*y^5*x^-2*y^-9 / 2
5x^(6+-2)* y^(5+-9) / 2
5x^4y^-4 /2 when you have a negative exponents you "flip" it to the bottom changing the negative sign to positive)
so 5 x^4 / 2y^4 or 2.5 x^4 y^-4

Answer 3

[20x^6/5y^9]/.[16x^2/10y^5]

I hope.

Well, invert and multiply:

(20x^6/5y^9)*(10y^5/16x^2)

20/5 = 4. 10/16 = 5/8. 4 * 5/8 = 5/2

x^6/x^2 = x^4

y^5/y^9 = 1/y^4

So, (5x^4)/(2y^4)

Edit: Missed the "16 x" the first time.

Answer 4

take each bracket as a separate problem a million/x - a million, you ought to make a straightforward dinumerator,x a million/x - x/x = (a million-x)/x do a similar for the 2d bracket a million/x + a million= a million/x + x/x = (a million+x)/x now end the artwork interior the huge bracket ((a million-x)/x) /a million-x)/x) bear in concepts that as quickly as you DIVIDE FRACTIONS you alter IT INTO MULTIPLICATION via THE RECIPROCAL, (a million-x)/x * x/(a million-x) = ( a million-x ) / ( a million+x ) now go returned to the unique problem a million - ( a million-x ) / ( a million+x )= ( a million+x ) / ( a million+x ) - ( a million-x ) / ( a million+x )= ( a million+x - a million +x)/( a million+x) 2x / ( a million+x)

Answer 5

(20*x^6/5*y^9)/(16*x^2/10*y^5)

Invert and multiply

(20*x^6/5*y^9)*(10*y^5/16*x^2)

= (5*x^4/2*y^4) = (5/2)x^4*Y^-4

Hope this helps.

Answer 6

wowowow.. can u phrase it better?