A coin is tossed four times. Write the sample space and find: a probability of all four tosses are heads?

Answer 1

misterbean is correct. there are 16 different possible outcomes. calculated by each coin has 2 possibilities. and your tossing the coin 4 times with replacement. equation for number of permutations (ie. possible outcomes) = 2^4 = 16

since the coin coming up heads 4 times is 1 of the 16 possibililites, the odds are 1:16

note that the possibilite of 1 tail + 3 heads = 4:16

Answer 2

undemanding: each and each time you toss a coin you have a threat of 0.50 (50%) of having heads, perfect? good, then in case you swap it 7 situations and in case you pass with for to have a fulfillment of four situations getting heads it is: 4/7 then your familiar threat ought to be: a million/2 (it is 0.50) x 4/7 = 4/14, decreased to 2/7 = 0.2857% meaning that, all situations met, in case you tossed a coin 7 situations, your threat of having 4 heads out of the 7 situations is extremely larger than 28%, it is that in case you repeat the workout habitual many situations (in case you toss the coin 7 situations many rounds) then 28% % of the time you will get 4 heads in step with each and each 7 toss around.

Answer 3

Sample Space:
HHHH, THHH, HTHH, HHTH, HHHT, TTHH, THTH, THHT, HTTH, HTHT, HHTT, TTTH, TTHT, THTT, HTTT, TTTT

Probability all tosses are heads: (1/2)^4 = 1/16

Answer 4

It's 50% because there is another side,



I just tried this and got 75% was heads,and 25% tails... But it is a 50% chance,if you used independent events!