A student's car stalls right in front of a speed bump while she is on her way to physics class. To pull it over the bump, she ties a cable to her bumper and to a nearby tree, and pulls with a force, F, of 84.0 lbs (374 N) at the midpoint in a perpendicular direction.
If θ is 10.5°, what is the size of the force pulling the car in lbs?
2007-03-13 14:46:51 · 2 answers · asked by saxeyamber009 1 in Science & Mathematics ➔ Physics
I guess θ is the angle the cable makes when she pushes on it. This is counteracted by F1 pulling the car and F2 pulling the tree.
So you have
|F| = 376N
|F1| = |F2|
F is oriented at 0 degree
F1 makes an (90-10.5) angle with F
F2 makes an -(90-10.5) angle with F
F1 + F2 + F = 0
|F1| = 376/sin(10.5) = 2063 N
2007-03-16 06:56:39 · answer #1 · answered by catarthur 6 · 0⤊ 0⤋
Assuming θ is the angle above the horizontal for which the student applies the force, then I think the answer is (in exact value)
84 / cos(10.5) = F
The question is worded weird, though, so I'm not sure.
2007-03-13 15:44:44 · answer #2 · answered by pedros2008 3 · 0⤊ 0⤋