what would (8+m)(8-m) be?

Question

I got 16 - m. But that doesn't even look close to being right.

Answer 1

64-8m+8m-m^2
64-m^2

Answer 2

The problem is: (8+m)(8-m)

Let's rearrange it to: (-m+8)(m+8)

Now let's take -1 out of (-m +8) so the equation becomes:
-1(m-8)(m+8)

(m-8)(m+8)=m²+8m-8m-64=m²-64

Distribute -1 into m²-64 and it will become -m²+64.

Check step: Plug in 1 to (8+m)(8-m)

9*7=63

-(1)²+64=-1 (exponent goes first) + 64=63

Solution (and other forms of solution):
-m²+64
64-m²
-(m²-64)

Answer 3

64 not 16. You almost had it right.
because if you use the distributive property then you have to do 8 X 8. you did 8 + 8

Answer 4

It would be
64-8m+8m-m^2 which when simplified =
-m^2+64
(The ^2 means squared)
Just remember FOIL
F-first: The first terms of each parentheses
O-outside: The outside terms of the parentheses
I-inside: The inside terms of the parentheses
L-last: The second terms of each parentheses

Answer 5

64-m^2 remember FOIL
8 x 8=64
8 x m=8m
8 x -m= -8m
m x -m= -m^2

so it is -m^2+8m-8m+64
or 64-m^2

Answer 6

Use the method of F.O.I.L. Multiply the first digits in each binomial, then the outer digits, then the inner digits, and finally the last digits. Then simplify.
I got -m squared + 64

Answer 7

i got 64 minus 2 square

Answer 8

(8+m) (8-m)
where
8 =a
+m= b
8 =c
-m=d
using > a.c a.d b.c b.d
= 64-8m+8m-m^2
=64-m^2

Answer 9

answer is 64 - m^2

The long version of the answer is 64 - 8m + 8m - m^2 ...

Hope you see that.

Answer 10

well with what im doing now it would be

64-m^2 but im not completly sure im only an 8th grader taking Algebra 1

Answer 11

64 minus m-squared