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A 15g marble is dropped from rest onto the floor 1.44m below. (a) If the marble bounces straight upward to a height of 0.640m what is the magnitude and direction of the impluse delivered to the marble by the floor? (b) If the marble had bounced to a greater height, would the impluse delivered to it have been greater or less than the impluse found in part (a)? Explain.

2007-03-13 13:55:02 · 1 answers · asked by christy r 1 in Science & Mathematics Physics

1 answers

ke = .5mv^2
pe = mgh
g=9.8
mass=.015kg gravitydecelleration=9.8m/s^2 height=.64m
A) .015*9.8*.64 = .094 Newtons
The direction is up.
B) greater

2007-03-13 14:02:26 · answer #1 · answered by Eric Inri 6 · 1 0

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