How do you balance chemical equasions?

Question

Answers i need:
P+O2------> P2O6
Na + H2O --------> NaOH+ H2
Ag2O --------> Ag + O2
S8 + O2 -------> SO3
CO2 + H2O -------> C6H12O6 +O2
K +MgBr2 --------> KBr + Mg
HCl + CaCO3 ---------> CaCl2 + H2O + CO2

Sorry, i couldnt find any way to do a subscript, so all of the numbers should be in a subscript.

Answer 1

4 the 1st 1, put a coefficient of 2 in front of phosphorous and a 3 in front of oxygen that makes the aquation true. a subscript tells how many atoms there are of that kind. a coefficient tells how many molecules. us ing this info, u can solve the rest

Answer 2

You should learn to do this yourself.
In #1, 2P are needed on the left to supply the P2 in P2O6. Check the oxygen requirement; 3O2 are needed. So you have 2P + 3 O2 -> P2O6

In #2 , the Na is OK, so the coefficient of Na will be the coefficient of NaOH. However the H is out of balance. To get it in balance, we double the coefficient. Then
2Na + 2 H2O -> 2 NaOH + H2

In #5, 6 CO2 balances out the C6 in glucose, so those coeffients are in a 6:1 ratio. 6 H2O provide the H12O6 in glucose. And there is a O2 left over.
So 6 CO2 + 6 H2O = C6H12O6 + O2

You should be able to work out the others.

Answer 3

When mixed together, the chemical elements balance themselves, some transforming into a new substance altogether, while some remain separable, one from the other.

The following is your result, when combining the listed elements:

1. Phosphorus Oxide
2. Sodium Hydroxide
3. Silver Oxide
4. Will not produce anything except salt water.
5. Carbon Hydroxide will result, however, your result, as listed in your question, would be a form of sugar, either High fructose or glucose, for sure, I am not.
6. Potassium Bromide
7. Calcium Carbonate, such as a bicarbonated soda or rolaids, tums or baking soda
8. Phosphoric acid

I don't know if this is what you were looking for. If not, let me know and I will try to help you. What are you trying to produce?

Answer 4

Balancing means you have the same amount of each atom on both sides...
So for #1 for example:
on product side (right side) you have 2 P atoms, so you but a number 2 in front of the P on the reagent side (left side). Then you have 6 O's on the right, so you add a 3 to the left side so you get 6O's on each side.
It's very easy... you may be confusing yourself by making it seem more difficult than what it is.

Answer 5

A chemical equation describes what occurs in a chemical reaction. The equation identifies the reactants (commencing factors) and products (ensuing substance), the formulation of the contributors, the stages of the contributors (good, liquid, gasoline), and the quantity of each substance. Balancing a chemical equation refers to installation the mathematical courting between the quantity of reactants and products. The parts are expressed as grams or moles.

Answer 6

2P + 3O2 ==> P2O6
2Na + 2H2O ==> 2NaOH + H2
2Ag2O ==> 4Ag + O2
S8 + 12O2 ==> 8SO3
6CO2 + 6H2O ==> C6H12O6 + 6O2
2K + MgBr2 ==> 2KBr + Mg
2HCL + CaCO3 ==> CaCl2 + H2O + CO2