what would (a+1)(a-1) be?

Question

I got a squared + 1a - 1 is that right?

Answer 1

Once you distribute you would get:
(a+1)(a-1)
Do a x a, then a x 1, then 1 x a, then 1 x -1
a(squared) -1
The 1a and the -1a will cancel each other out.
Hope this helps!

Answer 2

a^2-1

Answer 3

Just use the FOIL method.

That means, first multiply the First values within the parenthesis, then the outer, inner and last, so what you get is:

a^2 - a + a - 1
-a and a cancel each other out and you are left with:

a^2 - 1

Answer 4

I don't think so. Look at it as a two digit number multiplied by a two digit number... neg one time pos one is neg one..neg one times a is neg a. Now a times pos one is a and a times a is a squared. The neg a and the pos a equal zero a so you end up with a square minus one as the answer. Hope that makes sense.

Answer 5

(a+1)(a-1)
a^2-a+a-1
a^2-1

Answer 6

Actually, it's (a^2 -1).

When you multiply them together using the FOIL method, you get a^2 + a - a -1.

Answer 7

a to the 2nd power -1

Answer 8

no, it will be a square - 1.
a1 + (-a1) would cancel out leaving you with
a squared - 1

Answer 9

2a-1