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A pair of narrow, parallel slits seperated by 0.25 nm are illuminated by the green component from a mercury vapor lamp( lambda= 546.1 nm). The interference pattern is observed on a screen 1.20 m from the plane of the parallel slits. Calculate the distsance from the central maximum to the first bright region on either side of the central maximum and between the first and second dark bands in the interference pattern.

2007-03-13 13:38:31 · 2 answers · asked by Kitana 2 in Science & Mathematics Physics

2 answers

Use the equation

mλ=d∆y/L

Where
m=fringe number
λ=wavelength
d=slip separation
∆y=distance from center to fringe
L=distance from slits to screen

Although this is nonstandard, I use m=1/2 for the first order dark band and m=3/2 for the second. I think this is better than having two equations, one for bright and one for dark.

2007-03-13 13:49:04 · answer #1 · answered by 2 meter man 3 · 0 0

the unmarried slit bypass provides spatial coherence to the incident airplane wave which that's theory to return from a protracted monochromatic source. If the preliminary airplane wave become spatially coherent, then you certainly would not choose the 1st slit. you ought to use a laser no problem. If the laser spot length is sufficiently huge for the double slit, which probably is, then you certainly will see a similar effect and no choose for the 1st unmarried slit bypass may well be mandatory. I certainly have completed this test in the bypass with the two a protracted source and a laser; employing a laser is plenty much less complicated.

2016-11-25 01:34:41 · answer #2 · answered by Anonymous · 0 1

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