A man with blood type A and a woman with blood type B could ooooonever produce a child with blood type?

Question

How do do a punnett square for this question? I know there are 4 punnett squares

Answer 1

I can't draw squares of any type on the computer.
Anyhow, it depends on the parents' genotypes:

Father: could be AO or AA
Mother: could be BO or BB
So there are 4 possibilities :

1. AOxBO ====> children: AB, AO, BO or OO (equal probability)
2. AOxBB ====> children: AB, BO (equal probability)
3. AAxBO ====> children: AB, AO (equal probability)
4. AAxBB =====> all children AB (F1 of 2 homozygous parents are all identical)

In the case of blood type there is no dominance, as these antigens are co-expressed on the blood cell surfaces

Answer 2

To answer your leading question you would have to know the geneotypes of 1 or both parents. If the man happens to be AO and the woman happens to be BO, then all 4 blood types are possible in their offspring.

Answer 3

the blood type to mom could be bi and bi and dad could be ai and ai so by the punette square you could get a cross ii or in other words blood type O

Answer 4

They have a 25% chance of having a child with A, B, AB, or O

Punnett square: Dad is I^A i
Mom is I^B i

I^A i = A
I^B i = B
I^BI^A = AB
ii= O