ex. [ Bi(2)S(3) ]
solubilite= 8.2 x 10(-18)
and the gram-formula mass is 514.15
2007-03-13 08:35:27 · 3 answers · asked by Hiborn 1 in Science & Mathematics ➔ Chemistry
For this compound, Ksp= [Bi3+]^2[S2-]^3
Since when one formula unit of the compound dissolves, it produces 2 Bi3+ ions and 3 S2- ions, the concentration of Bi2+ ions in a saturated solution will be 2X the solubility, and the concentration of S2- ions will be 3X the solubility.
Plug those values into the expression for Ksp and you've got it.
Now, since you didn't put units on the solubility, I'm assuming that the solubility was given in mol/L. If it was given in g/L, you can divide that solubility by the formula mass to get the solubility into mol/L. Then go from there.
2007-03-13 08:41:41 · answer #1 · answered by hcbiochem 7 · 0⤊ 0⤋
You don't need the gram formula mass
Let solubility be s
So, Ksp = (2s)^2(3s)^3 = 108s^5
2007-03-13 15:45:56 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 0⤋
Mention units of solubilty.
2007-03-13 15:44:06 · answer #3 · answered by Anonymous · 0⤊ 0⤋