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Use the following information to calculate Delta Hlattice for MgF2.

Mg(s) --> Mg(g)
Delta H = 148 kJ

F2(g) -> 2F(g)
Delta H= 159 kJ

Mg(g) -> Mg+(g)+e-
Delta H = 738 kJ

Mg+(g) -> Mg2+(g)+e-
Delta H = 1450 kJ

F(g)+e- -> F-(g)
Delta H = -328 kJ

Mg(s)+ F2(g) --> MgF2(s)
Delta Hf = -1123 kJ

2007-03-13 07:53:49 · 1 answers · asked by socr8711 2 in Science & Mathematics Chemistry

1 answers

2962 kJ

2007-03-13 08:50:49 · answer #1 · answered by ag_iitkgp 7 · 0 0

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