Help!
A typical car gets 30 mi. per gallon of gas and drives 12,000 mi every yr. Assuming that octane (C8H18 0.7025 g/cm3) is a principal componnent of gasoline.
a. how much oxygen is required for a car to run for 1 yr?
b. how much CO2 (in grams) is produced by the car in 1 yr?
C. how many trees are required to remove the CO2 produced by the car in 1 year???
HELP!!!!!!!
2007-03-13 07:51:17 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
gal/30miles*12000mile/yr = 400 gals/yr
= 1.51 * 106 ml * .7025g/ml = 1.06 *106g
1.06 *106g*mole/114g = 9329.7 moles
2C8H18 + 25O2 --> 16CO2 + 18H2O
a) 1 mole C8H18 needs 25/2 moles O2
so 9329.7 moles needs 9329.7*25/2 =
116621 mole O2
b) 1 mole C8H18 make 8 mole CO2
so 9329.7 moles make 8*9329.7 =
74637.5 moles * 44gCO2/mole = 3.3*106 g CO2
c) how much CO2 can a tree remove?
2007-03-13 08:21:38 · answer #1 · answered by Dr Dave P 7 · 0⤊ 0⤋
Take 1 gallon as 2 litres or 2000cm3 and solve.
2007-03-13 15:36:50 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 0⤋