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Which of the following are true statements for the given compound in aqueous solution ?



a) NH3 : A Bronsted base and a Lewis base

b) HI : A Bronsted acid, but not a Lewis acid

c) CH3CH2CH2COOH : A Bronsted acid and a Lewis acid

d) Cu 2+(aq) : A Bronsted acid, but not a Lewis acid

e) CH3CH2CH2CH3 : Both a Bronsted acid and a Lewis acid


I Tried:
1) A,B,C
2) A,B

2007-03-13 07:48:08 · 3 answers · asked by Russell M 1 in Science & Mathematics Chemistry

3. B,C is also WRONG

2007-03-13 08:37:51 · update #1

A,C,D is also WRONG

2007-03-13 16:00:10 · update #2

3 answers

b and c

2007-03-13 08:35:40 · answer #1 · answered by ag_iitkgp 7 · 0 0

A Bronsted base is maximum more often than not seen as a substance that could settle for protons (hydrogen ions), at the same time as a Lewis base is any molecule or ion that could form a clean coordinate covalent bond, by ability of donating a pair of electrons. So a) is real ammonia can settle for a proton and may donate apair of electrons. compared to a Brønsted-Lowry acid, which always transfers a hydrogen ion (H+), a Lewis acid may be any electrophile (including H+). in spite of the undeniable fact that all Brønsted-Lowry acids are Lewis acids, in undemanding utilization the time period Lewis acid is oftentimes reserved for those Lewis acids which at the prompt are not Brønsted-Lowry acids. compared to a Brønsted-Lowry acid, which always transfers a hydrogen ion (H+), a Lewis acid may be any electrophile (including H+). in spite of the undeniable fact that all Brønsted-Lowry acids are Lewis acids, in undemanding utilization the time period Lewis acid is oftentimes reserved for those Lewis acids which at the prompt are not Brønsted-Lowry acids. b) in undemanding utilization hi is a Brønsted-Lowry acid and therefore no longer seen as a Lewis acid (in spite of the undeniable fact that that's). Sp that's real. c) Acetic acid can donate a proton and so that's a Brønsted-Lowry acid and so that's pretend. d) Copper Ion can't donate a proton, so that's pretend. e) butane can't donate a proton, so that's pretend. precis a and b are real, at the same time as c, d and e are pretend.

2016-12-01 22:48:19 · answer #2 · answered by ? 4 · 0 0

answers are ACD

2007-03-13 13:19:40 · answer #3 · answered by sara 2 · 0 0

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