I'm stuck on this physics question. There is a cylinder, full of water with three holes at different heights along the side. Water is constantly being pumped in to make up for any water coming out, so the water is at a constant height in the cylinder at all times.
Find the pressure at the top and the bottom of the cylinder.
I thought I would use Bernoulli's Equation, but i have no values for flow velocity or cross-section of the cylinder.
2007-03-13 07:23:46 · 3 answers · asked by Have_ass 3 in Science & Mathematics ➔ Physics
The pressure at the top is atmospheric.
You need the height of the cylinder (the water depth)
If your working with metric, 1 metre of water will exert 100g/cm² of pressure.
Multiply the height in metres by 100 = g/cm²
If working with Imperial (UK), 1 foot of water exerts 0.433 psi.
Multiply height in feet by 0.433 = psi.
2007-03-13 07:53:45 · answer #1 · answered by Norrie 7 · 0⤊ 0⤋
u need pressure at the top and bottom of the cylinder
so the water through the holes do not come into the picture
thus at the cylinder top the pressure is atmospheric pressure and at the bottom is Pa + hdg
where h is height of water column , d density and g acceleration due to gravity.
2007-03-13 07:34:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋
It's not Bernoulli's equation. It's easier than that. It's just the height of the water above the hole times density of liquid times acceleration due to gravity. That gives you the pressure at a point at some depth.
2007-03-13 07:30:12 · answer #3 · answered by Elisa 4 · 0⤊ 1⤋