How do you make up solutions of sodium hydroxide?

Question

I need to make 0.2, 0.4, 0.6, 0.8 & 1.0 M of NaOH from powder. I need to find out how to make them & how you got to the answer i.e. using the n=cv equation or any other eqautions. It would be very helpfull if you could get back to me asap as I need this pretty urgently. Thank you

Answer 1

to what volumes?

Answer 2

remember molarity is moles/lit er

so if you want a .2 molar solution plug in .2 = x/1 (just assuming you are using 1 liter could be whatever you want it to be)

then solve for X, wich will give you the amount of moles you need. Then once you have that, simply convert it to grams by multiplying it by the molecular weight of NaOH

Answer 3

I would start by making a large volume of 1M NaOH. To make a liter of 1M NaOH, dissolve 40g (1 mol) of NaOH in 1L of water. This works best, and most accurately, by adding the NaOH to about 500mL of water, then diluting to 1L.

From here, you can make as much as you need of your more dilute concentrations. Let's say you want to make 100mL (0.1L) of each concentration. Use the equation c1v1 = c2v2 to figure out how much of your 1.0M NaOH you want to use.

Example.
To make 0.1L of a 0.8M solution from 1.0M NaOH
c1 = 1.0M v1 = ??? c2 = 0.8M v2 = 0.1 L
1.0M * x = 0.8M * 0.1L
x = 0.08 mol / 1.0M = 80 mL.

Add 80 mL of your 1.0M NaOH solution to 20 mL of water to obtain 100 mL of 0.8M NaOH.

Answer 4

What apparatus do you have ?