English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Any help is appreciated on this. I don't really understand it.

Given: V = kq/(x^2 + y^2 + z^2)^1/2
I Found: E = [kq(x + y + z)]/(x^2 + y^2 + z^2)^(3/2)

Question: What charge distribution does the potential represent? (It doesn't ask why, but if you could explain I would be greatful, Thanks!)

2007-03-13 06:21:16 · 1 answers · asked by ecogrl23 2 in Science & Mathematics Physics

1 answers

V- voltage or energy per unit of charge
E- electric intensity or force per unit if charge

dV=Edr
so dV/dr=E where r=f(x,y,z)
then
: E = 2[kq(x + y + z)]/(x^2 + y^2 + z^2)^(3/2) (you were correct but you forgot the 2.

It is a point charge or is being treated as such.

2007-03-13 07:29:19 · answer #1 · answered by Edward 7 · 1 0

fedest.com, questions and answers