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a) CuCl2

b) CH3OH

c) CH3CH2OH

d) Hg

e) CH3CN

how can i solve this.
plz help me

2007-03-13 06:15:56 · 7 answers · asked by kcc 1 in Science & Mathematics Chemistry

7 answers

The easiest way is to look up solubilities by using chemistry books or the Internet.

a) Copper chloride is soluble.

b) Methanol is total soluble( it is polar and so will dissolve in water another polar molecule)

c) Ethanol is soluble (it is polar and so will dissolve in water another polar molecule)

d) Mercury will not dissolve in water.

e) Acetonitrile is total soluble in water.

2007-03-13 06:25:35 · answer #1 · answered by The exclamation mark 6 · 1 0

You have to look at each independently.

Copper chloride will dissolve since halide salts are well soluble in water

methanol CH3OH will dissolve extremely well since it has an OH group like water, and protic

ethanol will dissolve fairly well since it too has an OH group, but is a longer hydrocarbon chain, and still protic

acetonitrile CH3Cn dissolves moderately in water since it is polar but not protic.

mercury is a not only a metal but one that is fat soluble as well, and dissolves poorly in water if at all, before forming insoluble salts and dropping ot of the water with its impurities

2007-03-13 06:33:47 · answer #2 · answered by biophile6 2 · 0 0

I think so that CuCl2 bcuz it is an inorganic compound and Hg does not dissolve in water readily all other are organic hydrogen carbon containing componds. Go for the type of bonds and bonding of transition metals in some grade 11 or 12 chemistry book.

2007-03-13 06:24:53 · answer #3 · answered by Anonymous · 0 1

I know Hg will not disolve in water because it's mercury.

CuCl2 and CH3OH will...


I don't know anything about the others. Good luck.

2007-03-13 06:25:33 · answer #4 · answered by Im2hard2please 2 · 0 0

a), b), c), and e) are all very soluble in water

Hg is insoluble

2007-03-13 06:26:15 · answer #5 · answered by Dr Dave P 7 · 0 0

a b c and e

2007-03-13 06:25:47 · answer #6 · answered by Politicspassion 2 · 0 0

b and c

2007-03-13 06:28:27 · answer #7 · answered by ag_iitkgp 7 · 0 0

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