Updated Question: How do I search in Perl?

Question

I need to search for words in a txt file (see below) that begin with "p" and "P" and words that end with "p" and "P" and print them out. Thank the people who have helped me answer my previous question.

Text File:
CPAN stands for comprehensive Perl Archive Network.
^ and $ are used as anchors in a regular expression.
/pattern/ is a pattern match operator.
Perl is very easy to learn.
Enter 'H' or 'h' for help.

#!/usr/local/bin/perl
open INPUT, " while ()
{
my($line) = $_;
chomp($line);
if ($line =~ m\b\^p*\bi) {print "$&\n";}
if ($line =~ m/p$*/i) {print "$&\n";}
else {print "No match, sorry.\n";}
}
close INPUT;

The output is supposed to be:
Perl
pattern
pattern
Perl
help

But I only get:
P
p
p
P
p

How do I make the program print out the whole word?

Answer 1

if you broke them into words...

if ($word =~ /^p/i) {print "$word\n";}
if ($word =~ /p$/i) {print "$word\n";}

but as lines ....

if ($line =~ m/\b\w*p\b/i) {print "$&\n";}
if ($line =~ m/\bp\w+\b/i) {print "$&\n";}


that looks about right!

Answer 2

in \b\^p*\bi:
the ^p is redundant; \bp gets a p at the beginning of the word. p* gets any number of p's; what you really want is p.*, that is, p followed by whatever. You'll want to make that non-greedy, so p.*?. Finally, the if statement will only get the first instance in the line; you need a loop to get them all.
p$ matches a p at the end of the string, but none of what comes before it; not what you want.
So, try this instead:
while($line =~ m/\bp.*?\b/ig) {print "$&\n";}
while ($line =~ m/\w*p\b/ig) {print "$&\n";}

Answer 3

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