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Hello, could i have help with the following please?
The charge on the plates of a capacitor is 8mC when the potential between is 5kV. Determine the capacitance of the capacitor.

Cheers

2007-03-13 06:01:01 · 4 answers · asked by MoLeY 1 in Science & Mathematics Physics

4 answers

Capacitance = charge divided by voltage

2007-03-13 06:07:18 · answer #1 · answered by Gene 7 · 0 0

1.6micro Farads As Q=CV
Q charge
C capacitance
V potential difference

2007-03-13 13:09:40 · answer #2 · answered by Anonymous · 0 0

C = Q/V = 0.008/5000 = 1.6uF

2007-03-15 11:25:24 · answer #3 · answered by joshnya68 4 · 0 0

C = 1.6 microF

2007-03-13 14:23:02 · answer #4 · answered by ag_iitkgp 7 · 0 0

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