ca(oh)2 +2hcl > cacl2+2h2o
2007-03-13 04:59:34 · 3 answers · asked by jolee 1 in Science & Mathematics ➔ Chemistry
MW of HCl is 36.5 g/mol, therefore in 50g there are 50/36.5 moles = 1.37 moles.
From the equation above, half the number of moles of Ca(OH)2 will react with those of HCl. This makes 0.685 moles.
MW of Ca(OH)2 is 74.1 g/mol
therefore the mass needed is :0.685 * 74.1 = 50.75 grams
2007-03-13 05:19:31 · answer #1 · answered by Jesus is my Savior 7 · 0⤊ 0⤋
50g HCl in mole is 50/35.47 = 1.41mole
You see that 2 moles oh HCl react withone mole calcium hydroxyde so , you need only 1.41/2 = 0.705mole of Ca (OH)2
the molecular weight of Ca(OH)2 = 40+2*17 =74
so 0.705*74 =52.2g Ca(OH)2
2007-03-13 05:17:05 · answer #2 · answered by maussy 7 · 1⤊ 0⤋
Molecular weight of Ca(OH)2=seventy 4.093 gm/mole kind of moles=sixty one.8/seventy 4.093=0.834 mole 2HCl+Ca(OH)2-->CaCl2+2H2O 2 moles of HCL are required for a million mole of Ca(OH)2 X moles of HCl are required for 0.834 mole of Ca(OH)2 So, X= 2*0.834/a million=a million.668 mole Molecular weight of HCl=36.40 six gm/mole kind of grams of HCl required=36.40 six*a million.668=60.822 gm
2016-10-18 06:49:31 · answer #3 · answered by farraj 4 · 0⤊ 0⤋