25 cm3 of sulphuric acid was neutralised with 18.0 cm3 of sodium hydroxide 1.0 mol dm-3.?

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25 cm3 of sulphuric acid was neutralised with 18.0 cm3 of sodium hydroxide 1.0 mol dm-3.?

what is the molarity of sulphuric acid

2007-03-13 04:07:33 · 1 answers · asked by nazati 2 in Science & Mathematics ➔ Chemistry

1 answers

H2SO4+2NaOH = Na2SO4 +H2O
you need 2 molecules of NaOH for 1 molecule of acid .

So 18cm^3 of NaOH can neutralize 9cm^3 of 1.0 molar sulphuric acid

As you have neutralized 25cm^3

you can write 25 *molarity = 9*1

molarity = 9/25 = 0.36M

2007-03-13 04:46:26 · answer #1 · answered by maussy 7 · 0⤊ 0⤋