^3 square root of 6x = -3
2007-03-13 02:29:18 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
solve for x
6x = -3
6/6 x = -3/6
x = -1/2
square root of -.5 = .707
2007-03-13 02:36:02 · answer #1 · answered by Curly 4 · 0⤊ 0⤋
I assume you mean the cube root of 6 = -3 this can be written as:
(6x)^1/3 = -3
cube both sides:
6x = -27
x = -27/6 =9/2
2007-03-13 03:33:35 · answer #2 · answered by bignose68 4 · 0⤊ 0⤋
sqrt(5x + 29) = x+ 3 sq. the two components 5x + 29 = x^2 + 6x + 9 Now isolate the equation to a minimum of one area and set it to 0. 0 = x^2 + x - 20 Now element and clean up for x. 0 = (x+5)(x-4) x = -5 or 4
2016-12-14 17:52:53 · answer #3 · answered by hannigan 4 · 0⤊ 0⤋
What do you mean with [ ^3 ] ?????
Can I understand that are you asking
(6X)^(1/3) = -3 (the cubic root of 6X = -3)?
If I'm correct:
(6X)^(1/3) = -3 ==> [(6X)^(1/3)]^3 = [-3]^3
6X = -27
X = -27/6
X = -9/2
2007-03-17 00:26:47 · answer #4 · answered by Apolo 6 · 0⤊ 0⤋