factor completley (show and describe steps)?

Question

x^2-7x-8

Answer 1

Given exp
=x^2-8x+x-8
=x(x-8)+1(x-8)
=(x+1)(x-8)

Answer 2

Completing the square method

x² - 7x - 8 = 0

x² - 7x - 8 + 8 = 0 + 8

x² - 7x = 0

x² - 7x + ______ = 8 + ______

x² - 7x + 49 / 4 = 8 + 49 / 4

(x - 7/2)(x - 7/2 = 32/4 + 49/4

(x - 7/2)² = 81/4

(√x - 7/2)² = ± √81 / √4

x - 7/2 = ± 9/2

x - 7/2 + 7/2 = 7/2 ± 9/2

x = 7/2 ± 9/2

- - - - - - - - - -

Solving for +

x = 7/2 + 9/2

x = 16/2

x = 8

- - - - - - - -

Solving for -

x = 7/2 - 9/2

x = - 2/2

x = - 1

- - - - - - - - - - - - -

Method 2

x² - 7x - 8 = 0

Find the sum of the middle term

x = 1

Multiply the first term by the last term and factor

1 x 8 = 8

Factors of 8 = 1, 2, 4, 8

- 8 and + 1 satisfy the sum of the middle term

x² - 7x - 8

x² + x - 8x - 8

x(x + 1) - 8(x + 1)

(x - 8)(x + 1)

- - - - - - -

Roots

x - 8 = 0

x - 8 + 8 = 0 + 8

x = 8

- - - - - - -
Roots

x + 1 = 0

x + 1 - 1 + 0 - 1

x = - 1

- - - - - - - - s-

Answer 3

Let's make your problem more general ax^2+bx+c where a, b, c can be any integer ie 0, +-1, .... . You want 2 integers that can multiply to get a and two integers that multiply to get c. List them out, cross multiply the results and add them to get the b coefficient.

In your case. x^2 - 7x - 8
a=1, b=-7, c=-8

2 integers that multiply to get a(1) would be 1 x 1. So list it vertically.
1

1
2 integers that multiply to get a(-8) would be 1x-8. So list it vertically next to the previous combination to form a grid.

1 1

1 -8
Now when you cross multiply and add up the sum 1x-8 + 1x1 = -7 which is equal to the b coefficient.

Now just read across the grid horizontally. (1x + 1)(1x-8) and your done.

x^2 -7x -8 = (x+1)(x-8)

Now order doesn't matter. Whenever you factor, it takes some trial and error to find the right "grid". Practice often helps speed up this process.

Answer 4

It is x in the 2nd power x².

they cannot write it in the proper form so they write x^2.

and for those who need more info about this, they supposed to use the alt key 253 then the power of 2 will appear like this ².

in this case:

factoring:
x²-7x-8

= x²-8x + 1x-8

=x(x-8)+ 1(x-8)

=(x+1) (x-8) ...................ans

and if you want to find out the value of x, you may use
the quadratic formula for this.

ax+bx+c=0

x = -b+-[b²-4ac]/2a

there will be two answers:
x = 8 and the other answer will be x = -1

Answer 5

What 2 numbers multiplied equals -8 and added equal -7?
-1 and 8: no
1 and -8: yes

x^2-7x-8
=(x+1)(x+(-8))
=(x+1)(x-8)

Answer 6

is that 2X? What is the symbol between X and 2?
If it is supposed to be x+2-7x-8...solve for x
-6x -6 = 0
-6x = 6
x = -1

Answer 7

x²-7x-8 =
(x - 8)(x + 1)
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Answer 8

x^2 - 7x - 8
what two numbers multiply to 8 and subtract to 7? 8 and 1

(x+1)(x-8)
you can foil it to check your answer if you would like

Answer 9

x^2-7x-8

x^2-8x+1x-8

x(x-8)+1(x-8)

(x+1)(x-8)

are the factors of the eqn

Answer 10

you should find two numbers that have the summation equal to -7 and multiplication equal to -8. those two numbers are -8 and +1. after finding these two numbers you can write:
(x-8)(x+1)