1. (15x^3 - 19x^2 - 14x + 16) / (5x - 3)
2007-03-13 00:47:38 · 2 answers · asked by helllo1234 1 in Science & Mathematics ➔ Mathematics
it is hard to show this but i will do my best
...........3x^2 -2x -4
.....................................................
5x-3|15x^3 - 19x^2 - 14x + 16
........15x^3 - 9x^2
..................................
....................- 10x^2 - 14x + 16
....................- 10x^2 + 6x
........................................................
-20x + 16
-(-20x + 12)
.......................................................
4
so i get 3x^2 - 2x - 4 with 4 remainder
2007-03-13 02:13:33 · answer #1 · answered by Bill F 6 · 0⤊ 0⤋
just divide using simple rules of division of algebra.
the answer is 3x^2-2x-4 with 4 as remainder.
2007-03-13 01:03:50 · answer #2 · answered by Mayank B 1 · 0⤊ 0⤋