A single logarithm of 9 log(b) x - 3 log(b) y?

Answer 1

9 log[base b](x) - 3 log[base b](y)

First, move the 9 and the 3 inside the log as a power.

log[base b](x^9) - log[base b](y^3)

Now, combine the logs; note that a difference of logs means division inside the log.

log[base b]( x^9 / y^3 )

Answer 2

9log(b)x-3log(b)y=log(b)(x^9)-log(b)(y^3)
=log(b)((x^9)/(y^3))
=log(b)((x^3/y)^3)
=3log(b)(x^3/y)

Answer 3

=log(b)x^9-log(b)Y^3
=log(b)[x^9/y^3]
=log(b)[{x^3/y}^3]
=3log(b)[x^3/y]