2007-03-12 19:34:29 · 4 answers · asked by Emily S 1 in Science & Mathematics ➔ Mathematics
I guess you want to simplify this to the log of a single term. The coefficient of a log can be changed to be the exponent of the argument of the log operation. When a log is subtracted, you can instead divide the argument of the first log operation by the argument of the second log operation. When exponential expressions with the same base are multiplied together, the exponents are added.
9*log(bx) - 3*log(by) =
log[(bx)^9] - log[(by)^3] =
log[(b^9)(x^9)] - log[(b^3)(y^3)] =
log{[(b^9)(x^9)]/[(b^3)(y^3)]} =
log[(b^6)(x^9)/(y^3)]
2007-03-12 19:47:05 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
6 log b z
2007-03-13 02:38:38 · answer #2 · answered by Anonymous · 0⤊ 1⤋
log b [x^9/y^3]
2007-03-13 02:40:10 · answer #3 · answered by djin 2 · 0⤊ 0⤋
whats your question??? solve for x? or solve for y?? would be nice to know the question
2007-03-13 02:37:35 · answer #4 · answered by Curiously 5 · 0⤊ 0⤋