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x = -b plus or minus the square root of b² - 4ac over 2a

2007-03-12 19:33:04 · 6 answers · asked by Electriksz 2 in Science & Mathematics Mathematics

ok, i get it through x= -4 ± the square root of 24 over 2... then i'm lost

2007-03-12 20:14:39 · update #1

6 answers

x = [- 4 ±√(16 + 8)] / 2
x = [- 4 ± √24] / 2
x = [- 4 ± 2√6] / 2
x = - 2 ± √6
x = 0.45, - 4.45

2007-03-12 21:50:15 · answer #1 · answered by Como 7 · 0 0

Here in this equation, a=1, b= +4 and c= -2

therefore, applying the formula,we get,

x= -(+4) +- root of (+4) square - 4.1(-2) the whole upon 2(1)

= -4+- root of 16 + 8 whole upon 2
= -4 +- root of 24 whole upon 2
= -4 +- 2 root of 6 whole upon 2
= -2 (2 +- root of 6) whole upon 2
= -2 -+ root of 6

2007-03-13 02:47:08 · answer #2 · answered by NS 1 · 0 0

make ur x as a ,4x as b, and -2.then,fill the formula wt these info.as in,-(b)+-square root (4)to the power of 2 minus 4(1)(-2) over 2(1).ure supposed to get 2answers.the answers r:

- 4.4495 and 0.4495.i hope this helps

2007-03-13 03:04:22 · answer #3 · answered by shanukitty 1 · 0 0

Okay, if you have the formula, you can solve this on your own.
All of these are like:
ax^2 + bx + c = 0

in your case,
a = 1
b = 4
c = -2

just plug the numbers in... and remember the answer could be from the +ive or -ive square root, so plug the answers in to see which is the correct answer.

2007-03-13 02:39:44 · answer #4 · answered by Loulabelle 4 · 0 0

Delta=4^2-4x(-2)=24
X1=(-4+sqrt(24))/2
X2=(-4-sqrt(24))/2
'''sqrt(24)=2*sqrt(6);
if in the quadratic eq. b(coefficient of x) is even --like this eqn.-- we can write:
Delta'=(b/2)^2-ac
X1=(-b+sqrt(Delta'))/a
X2=(-b-sqrt(Delta'))/a

2007-03-13 02:58:20 · answer #5 · answered by arman.post 3 · 0 0

discriminant=16+4*2
=16+8=24
x1=(-4-2sqrt6)/2=-2-sqrt6
x2=-2+sqrt6

2007-03-13 02:38:24 · answer #6 · answered by djin 2 · 0 0

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