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yummy theta, and arctangents!?

If arctan 3/5=θ, what is arccsc(cotθ)?

2007-03-12 18:38:12 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

1 answers

arctan(3/5) = θ
tanθ = 3/5

sinθ = 1/cscθ and tanθ = 1/cotθ so

arccsc(cotθ) = arcsin(tanθ) = arcsin(3/5) ≈ 36.869898°

2007-03-12 18:47:20 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋

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