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this is a formation reaction with 1 mol of KCl on the right side of the reaction hence the reaction for this delta h you ask is

K(s) + 1/2 Cl2(g) -----------> KCl(s)

that's it and the delta H must be given you possibly ant calculate it.

2007-03-12 18:31:47 · answer #1 · answered by Bap 1 · 0 1

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