how do you find the distance between of a set of points? ex: (0,5) and (5,0)?

Question

like just the beginning part, is it x1 minust x2 devided by y1 minus y2, or y1 minus y2 devided by x1 minus x2, or y1 minus x1 devided by y2 minus x2 or x1 minus y1 devided by x2 minus y2 or y2 minus x2 devided by y1 minus x1 or whattt???

Answer 1

The formula is sqrt{(x1-x2)^2+(y1-y2)^2}
Now put the values of x1,x2,y1 andy2 in the formula
We get the distance
=sqrt{(0-5)^2+(5-0)^2}
=sqrt(25+25)
=sqrt50
=5sqrt2

Answer 2

Let the given points be A(0,5) and B(5,0).

Here , x1 =0 and x2 = 5
y1 =5 and y2 = 0.

Distance between the 2 points = Square root of [( x2-x1)the whole square + (y2-y1)the whole square]

Diatance between A and B = Square rrot of[( 5-0)the whole square + (0-5)the whole square]

=Square root of[ (5^2) + (-5^2)]

=Square root of(25+25)

= Square root of 50

=7.07106 =7.07 cms.

Therefore ,Distance between A and B = 7.07 cms

Answer 3

You're thinking of the slope formula not the distance formula.
Here's the distance formula:
d=sqrt[(x2-x1)^2+(y2-y1)^2]

Answer 4

find the differences between the x-coordinate and y-coordinates. Doesn't matter whether you do x1-x2 or x2-x1 (and similiarly for y).

Square (this is why it does not matter which way you find the difference, the square for both is the same, and that is what you need) and add these two differences.

Find the positive square root of the sum - that is the distance.

sum of squares = (0-5) ^ 2 + (5-0) ^ 2= 25

distance = positive sq. root of 25= 5

Answer 5

the distance formula is D = sqrt((x1-x2)^2+(y1-y2)^2)
so for (0,5) and (5,0) you would get
sqrt((0-5)^2+(5-0)^2) = sqrt(50)

Answer 6

Use the Pythagorean theorem. the line will be the hypotenuse of a right triangle whose legs are Δx & Δy.
Δx=|5-0|=5
Δy=|0-5|=5
the distance d=√(5^2+5^2)=√50
d=5√2=7.071