OK i think im looking for Efc(centriphical force) so i got this info.
MARS
mass: 641850000000000000000000
radius: 3.397000
distance from sun: 227936640 ... is this number equal to 2.2793664x10^11??
and the quesrion is asking me to find the force on a 1-kg object at the planets surface so i dont know if to use V2= G(m2)/r
or just use m(v2)/r
what do you ppl think??
2007-03-12 17:17:29 · 3 answers · asked by Rosa M 1 in Science & Mathematics ➔ Physics
no this question does not include any of Newtons Law's just want to say that.
2007-03-12 17:51:36 · update #1
I think more girls should say that.
about the equation thing tho....not too sure
2007-03-12 17:25:43 · answer #1 · answered by vito b 3 · 0⤊ 0⤋
You don't need the distance from the Sun for this question. All you nead is the radius and the mass of Mars. Then it's
F = G*m1*m2/r² where G is 6.67*10^(-11) Nm²/kg², m1 and m2 are the mass of Mars and the 1 kg mass, and r is the radius of mars (in meters).
HTH âº
Doug
2007-03-13 00:27:32 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
You need to review Mars' values and include units:
http://en.wikipedia.org/wiki/Mars
Then, you need to review Newton's Law of Gravitation:
http://en.wikipedia.org/wiki/Law_of_universal_gravitation
2007-03-13 00:49:32 · answer #3 · answered by arbiter007 6 · 0⤊ 0⤋