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The force of repulsion that two like charges exert on each other is 3.0 N. What will the force be if the distance between the charges is increased to 6 times its original value?

2007-03-12 16:41:11 · 1 answers · asked by Cameron 2 in Science & Mathematics Physics

1 answers

1/36th due to the inverse square law = 3/36 = 1/12 N

2007-03-12 16:49:12 · answer #1 · answered by Zefram 2 · 0 0

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