double slit diffraction?

Question

how do you calculate the speed of sound from the double slit diffraction experiment if you have plotted distance vs. intensity (v)
thank you!

Answer 1

You're supposed to figure out the frequency of sound, not the speed of it, because the speed of sound is a constant. How you figure out the frequency is as follows, given that S = f λ, where S is the speed of sound, f is the frequeny in Hz, and λ is the wavelength of that particular sound frequency. For the double slit experiment, the equation is:

d Sin(θ) = n λ

where d is the spacing of the double slit, θ is the angle of the line from the center of the double slit to any maximum sound intensity on the back "wall", n is an integer, as in 1st maximum, 2nd maximum, etc., and λ is the frequency. As an approximation, you can just use:

d (x / L) = n λ

where x is the distance of the maximum from the center along the back wall, and L is the distance from the double slit to the back wall. To get the frequency, we use the equation S = f λ,

d (x / L) = n (S / f)

f = (n S L) / (d x)

So, what you do is to measure L, d, and count n maximums from the center and measure x, and use the speed of sound which is about 344 m/sec, and calculate the frequency. Be sure you use a consistent measure, such as everything in meters.

Answer 2

i choose to declare which you will no longer even use easy bulbs. you are able to purely use coherent easy, which quantities to lasers. often the slits are so close that a great-unfold laser's diameter is gigantic sufficient to conceal the two slits. in addition to, the laser easy is in section with itself. 2 diverse lasers may well be out of section, producing a random trend first of all. the theory which you will shine a very centred laser on one slit, and a 2d centred laser on the different slit to produce an interference trend shouldn't artwork. you are able to say definitively that this photon went by using this slit, and that one went by using the different slit. hence, you get what you assume : bullets. You get 2 vivid spots in the back of each slit. yet once you are able to no longer say the place each photon went then that's mentioned to have long handed by using the two and interfered with itself. hence, your interference trend with a million easy source and 2 slits. i'm not sure what might happen in case you had 2 somewhat huge unfold laser beams whose beams the two strike the two slits. As I mentioned, the two diverse beams must be out of section with one yet another. this ought to alter the place the extrema happen, yet there ought to nonetheless be some (the possibility being a undeniable section which forces each little thing to combine to type a continuing, so which you get a unmarried dim line of continuous intensity). you are able to no longer administration the portion of each laser, and luckily with a million laser that section is irrelevant. this is named an "absolute section."