nickel (II) sulphate?

Question

suppose some nickel (II) sulphate was carefully placed in the bottom of a beaker of water. the beaker was then covered and left for several days. what will happen few hours and several days later? second, explain it with kinetic theory. third, what is the name of the physical process that takes place in this experiments?

Answer 1

The first thing that will happen is that the Nickel sulfate will combine with the water to form the hexahydrate:

NiSO4 + 6 H2O --> NiSO4*6H2O

This will happen almost immediately, with the yellow-green powder forming blue-green crystals.

The hexahydrate will then slowly disolve in the water, forming NI+2 and SO4-2 ions.

In terms of kinetics, the hydrogen bonding of the solvent H2O molecules breaks the crystal lattice into separate ions.

The physical process is the formation of a solution, which you can see as the color spreads through the water by diffusion.