Rate expression?

Question

The reaction" NO + 1/2Br2 > NOBr is second order with respect to NO and first-order with respect to Br2. The rate constant is 1.33 x 10^-4 L^2/mol^2/min.

What is the rate expression for this reaction?

Answer 1

The rate expression will have the form:

rate=k[Br2]^m[NO]^n

The rate constant is the value you've been given, and the exponents m and n are the orders of the reaction with respect to each of the reactants. In your case, m=2 and n=1.