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Find the molar mass for Ca3(PO4)2
(the 3,4, and 2 should be suscript)
If you have time, please explain to me HOW you got your answer. Thank you!

2007-03-12 13:32:17 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

First, you need a periodic table

on the periodic table, find the elements Ca, P, and O because they are part of the equation
after you find elements, you should see their molar mass written below them

now you multiply that mass by how many atoms are in the formula
so, Ca=40.1, but since you have 3 of those, you have to multiply 40.1*3=120.3
similarliy:
P=30.97, and you have 2 of those
30.97*2=61.94

O=16.00 and you have 8 of those
16*8=128

now after you find that, you add them up and you get:
120.3+61.94+128=310.24g/mol

2007-03-12 14:59:54 · answer #1 · answered by blueboy3056 3 · 0 0

First get next to a period table.

Here is an excellent one:
http://www.webelements.com/

You'll find that the molar masses of each of the elements is about
Ca→40 grams/mole
P→31 grams/mole
O→16 grams/mole

Ca3 means 3 calciums
3*40=120

(PO4)2 means 2 PO4's
So find the molar mass for PO4 and then multiply by 2.

2007-03-12 13:40:32 · answer #2 · answered by 2 meter man 3 · 0 0

Find each element on the periodic table. Multiply the mass of each element by the subscript of each element.

Ca3(PO4)2

Ca = 40 x 3 = 120
P = 31 x 2 = 62
O = 16 x 8 = 128
mass = 310

2007-03-12 13:36:58 · answer #3 · answered by physandchemteach 7 · 1 0

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