Pathagorean Therum. is that how u spell it?

Question

okay. what do u do when u have to deal with a problem like this?
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formula is................(a)squared + (b)squared= (c)squared.

(c)squared is the side longer than the other two sides in a right triangle.
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[10 * sqrt(2)] squared = (n)squared + (10)squared





plz tell and show me step by step on how to solve this problem.

Answer 1

It's actually called "Pythagorean Theorem".

Answer 2

so i'm assuming this is the problem:
SQ=square root
^2=squared

[10(SQ)2]^2= n^2+10^2 << [10SQ2]^2 becomes (100*4) which is 200 .... and 10^2 is 100 so thus:

200 = n^2+100 <
200-100 = n^2 <<200-100 is 100

100 = n^2 << take the square root of both sides (which is equivalent of saying raise the both sides to one-half)

SQ(100) = SQ (n^2) << square root of 100 is ten while square root of n^2 is n

10 = n

i hope that helped :) .. oh and it's spelled pythagorean theorem

Answer 3

Pythagorean Theorem=
a2+b2=c2

*the 2s are supposed to be exponents