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the difference between the first and last digits is equal to one, the sum of the digits is less than eight, the product of the first and last digit is greater than 3, the sum of the first two digits is equal to five, what is the number

2007-03-12 11:46:50 · 4 answers · asked by James L 1 in Education & Reference Homework Help

4 answers

32... I think that you will see why without need for explaination. don't assume that there has to be more than just the two digits.

2007-03-12 11:50:51 · answer #1 · answered by some_old_spanish_minor_in_school 2 · 0 0

OK, so the number has at least two digits. Let the first digit be x and the second digit be y. Assume that x>y.

So, according to the conditions:

x-y=1
x+y<8
xy>3
x+y=5

Adding the first and the last conditions gives us

2x=6, so x=3, and y=5-x=2.

So, one possible answer is 32, since (3+2)<8 and (3)(2)>3. However, there are many other answers that might work too. For example, 23 is also a possible answer. And you can get other possible answers if you assume that the number has more than three digits.

2007-03-12 19:16:45 · answer #2 · answered by pyaarmusafir 2 · 0 0

3-2=1
3+2=5
3*2=6
3+2=5

the answer is 32

2007-03-12 19:07:03 · answer #3 · answered by hon3ysmil3z 2 · 0 0

322

3-2=1
3+2+2=7
3*2=6
3+2=5

2007-03-12 18:54:19 · answer #4 · answered by Erica H 2 · 0 0

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