A 920 N crate rests on the floor.
(a) How much work is required to move it at constant speed 6.6 m along the floor against a friction force of 180 N?
J
(b) How much work is required to move it at constant speed 6.6 m vertically?
J
2007-03-12 07:32:00 · 3 answers · asked by nafiseh g 1 in Science & Mathematics ➔ Physics
Work is force times distance.
The friction force is given.
The gravitational force is mg.
Plug and chug.
2007-03-12 07:38:47 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Work = F x displacement
The work required depends on the distance travelled, the longer the distance the more the work. You cannot therefore work out the work since you do not supply the distance,
The power used in maintaining it at a constant speed 6.6m/s (by the way your units for speed are wrong!) is P = Fv = 180 x 6.6 = 1188 watts
2007-03-12 14:49:00 · answer #2 · answered by physicist 4 · 0⤊ 0⤋
The work is the force times the distance, so long as the distance is in the same direction as the force.
a) The force required to move it is 180N across the floor. The distance is 6.6m. Thus 180N times 6.6 meters is 1188 J.
b) To move it vertically, you need 920 N. 920N times 6.6 meters is 6072
2007-03-12 14:42:30 · answer #3 · answered by Nicknamr 3 · 0⤊ 0⤋