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1)BbTt
2)BBTt
3)BbTT
4)BBTT
5)bbtt
What am I missing that would help me to determine this on my own?

2007-03-12 06:49:59 · 2 answers · asked by Baby8Grl2000 3 in Science & Mathematics Biology

I actually figured it out shortly after I posted the question. I felt so dumb!

2007-03-14 07:08:10 · update #1

2 answers

Each gamete will have only one type of allele so:
1. could produce B, b, T and t
2. B, T and t
3. B, b, and T
4. B and T
5. b and t

2007-03-12 06:56:02 · answer #1 · answered by Curiosity 7 · 2 0

Imagine that the organism in question has two chromosomes, represented by X1 and X2, and assume that the two genes (B or T) are on different chromosomes. Because each chromosome is composed of two daughter chromatids, and there is a gene for the characteristic on each chromatid, an individual can be BBTT, BBTt, BBtt, BbTT, BbTt, Bbtt, bbTT, bbTt or bbtt. When the individual produces gametes, the daughter chromatids separate. Therefore chromatid one can go with either of the chromatids from X2, as can chromatid 2. The easiest way to figure it out for your self is to make a square of 4 boxes. Put the first gene on the top (one letter for each daughter chromatid above each of the two squares on top) and the second along the left side (again, one next to the two squares on the left. This diagram is called a Punnett suare (http://en.wikipedia.org/wiki/Punnett_square). Then,
copy the letters down the columns from the top and across the rows from the side. In the boxes in the square will be the possible combinations that can be made.

2007-03-12 17:24:09 · answer #2 · answered by kt 7 · 0 0

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