what is the emp of the cell?

Question

Zn|Zn2+(1.00M)||K3Fe(CN)6(0.10M), K4Fe(CN)6 (0.10M)|Pt

Answer 1

You need to give us the standard potentials and define the temperature of the cell. The overall reaction is

Zn + 2Fe(CN)6(-3) <=> Zn(+2) +2Fe(CN)6(-4)

Then we can use the Nernst equation

E=E0 -(RT/nF) * ln ([Zn+2]*[K4Fe(CN)6] / [K3Fe(CN)6])

with E0= E0cathode -E0anode

According to http://www.northland.cc.mn.us/Chemistry/standard_reduction_potentials.htm

Fe(CN)6 (-3) +e -> Fe(CN)6 (-4) E0=+0.358 V =E0cathode
Zn+2 +2e -> Zn E0= -0.7618 Volt =E0anode

so E0= 0.358-(-0.7618) =+1.1198 Volt

n is the number of e participating in the reaction, here n=2.
For 25 Celsius T=273+25=298 K so

E= 1.1198+ ( 8.314*298/(2*96485) ) *ln(1*0.1/0.1) =+1.1198 Volt (you have ln1 which is equal to 0)

Answer 2

Emp isn't part of a cell. It stands for Electromagnetic pulse and there is a lot of research going on at the minute into whether EMP can be used to help cancer patients by blasting the tumor.

However, as with all new discoveries and technologies, there is always the down side that it could be used as a bomb, perhaps even a weapon of mass destruction. This weapon could eradicate all biological life while leaving buildings and property intact for the attackers to enjoy.