10x - 1/4 = 9x + 3/8
2007-03-12 05:15:27 · 8 answers · asked by oklongbunch@sbcglobal.net 1 in Science & Mathematics ➔ Mathematics
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2007-03-12 05:16:06 · update #1
10x - 1/4 = 9x + 3/8
Minus 9x from both sides
10x - 1/4 - 9x = 9x + 3/8 -9x
x - 1/4 = 3/8
Add 1/4 for both sides
x - 1/4 + 1/4 = 3/8 + 1/4
x = 3/8 + 2/8
x = 5/8
2007-03-12 05:20:47 · answer #1 · answered by seah 7 · 1⤊ 1⤋
10x-1/4 = 9x +3/ 8
10x-9x=3/8 + 1/4
x = 5/8
2007-03-12 05:21:19 · answer #2 · answered by Simran 3 · 0⤊ 1⤋
10x - 1/4 = 9x + 3/8 subtract 9x from each side
x-1/4=3/8 add 1/4 to each side
x=3/8+1/4 get in LCD
x=3/8+2/8 add
x=5/8
2007-03-12 05:38:04 · answer #3 · answered by yupchagee 7 · 0⤊ 1⤋
10x - 1/4 = 9x + 3/8
10x - 2/8 = 9x + 3/8
10x = 9x + 5/8
x = 5/8
2007-03-12 05:21:55 · answer #4 · answered by math freak 3 · 0⤊ 1⤋
mmc(8 e 4) = 8
10x - 9x = 3/8 + 1/4
x = (3 + 2)/8
x = 5/8
Solução: {x pertence a R| x = 5/8}
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2007-03-12 07:58:07 · answer #5 · answered by aeiou 7 · 0⤊ 0⤋
80x/8 - 2/8 = 72x/8 + 3/8
80x - 2 = 72x + 3
80x - 72 x = 3 + 2
8x = 5
x = 5/8
2007-03-12 05:22:54 · answer #6 · answered by Anonymous · 0⤊ 1⤋
multiply both sides by 8
80x - 2 = 72 x + 3
80x - 72x = 3 + 2
8x = 5
x = 5/8
2007-03-12 05:20:52 · answer #7 · answered by Anonymous · 0⤊ 1⤋
2x + 2y = 20 making use of the simultaneous technique 2x - 2y = 4 ____________ 4x = 24 ( divide by ability of four) x = 6 replace x in between both equations 2x + 2y = 20 2 (6) + 2y = 20 12 +2y = 20 2y = 20 - 12 2y = 8 (divide by ability of two) y = 4 answer : X = 6 , Y = 4
2016-12-01 21:23:46 · answer #8 · answered by maritza 4 · 0⤊ 0⤋