temperature and volume?

Question

if the temperature of an ideal gas is raised from 100 degrees c to 200 degrees c, while the pressure remains constant, the volume does what?
does it double? stay the same? im confused!

Answer 1

Always start with PV=nRT

if P, n, R are constant then

V1/T1 = constant = V2/T2

if T1 = 100 and T2 = 200

the V1 must be 1/2 V2 to make the equation work

V1/V2 =100/200 = 1/2

V1/V2 = 1/2 ==> V1 = 1/2V2

Answer 2

PV = RT is the equation to remember and understand. So, if P remains same and T is increased from 100 to 200 C, the Volume does not remain same, but it does not become double also. T used here is the Kelvin scale, so 100 C = 373 and 200 C = 473 Kelvin. So,

P1V1 = R T1 and P2V2= RT2

P1V1/T1 = P2V2/T2

V2/V1 = P1.T2/P2.T1
Since P remains consant, P1 = P2

So, V2/V1 = T2/T1 = 473/373

Answer 3

"The volume of a gas is directly proportional to its absolute temperature".

Temperature MUST be in Absolute figures.
°C = 273 = K

100°C + 273 = 373: ... 200°C + 273 = 473 K.
The volume will increase but not double but will be about 1.27 times the original volume.

Answer 4

the formula pV=nRT
in your problem n and p remain constant

so you have if T increses , V increases

first caseT100= 273+100= 373K ; T200= 273+200= 473

so V200/V100 = T200/T100= 473/373 =1.268

V at 200C = 1.268* V at 100°C

Answer 5

P V = nkT

n and k are constants.
If T doubles but P is constant then V must double....

Volume doubles if Pressure is kept constant