A force of 50 N is applied continuously to a 5 kg block sitting on a frictionless table. The speed of the?

Question

block 10 s after the force was first applied is

Answer 1

The motion of the block will follow the equation

v(t)=v0+a*t

assuming v0 to be zero,
and F=m*a
so
a=F/m

v(10)=10*5/50
v(10)1 m/s

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