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Integrated law : 1/At = 1/Ao + kt
Or At^-1 = Ao^-1 + kt
Plotting 1/[conc A] vs time will give a straight line.. The above is the linear form.

T1/2 = 1/(k x Ao)

Keep in mind that you are using fractions in the solution of these problems.

2007-03-12 01:55:54 · answer #1 · answered by docrider28 4 · 0 0

the two the above solutions are best aside from the sign different than for the connect up ok: on condition that -d[A]/dt = ok[A]^a million/2 (unfavourable on condition that [A] is reducing), -ok dt = d[A]/[A]^a million/2 = [A]^-a million/2 d[A] and -ok t (t - 0) = 2[A]^a million/2 ([A] - [A0]) or -kt = 2[A]^a million/2 -2[A0]^a million/2. Rearranging, [A]^a million/2 = [A0]^a million/2 - (ok/2)t I ran into this subject attempting to derive the 2d order fee regulation final 12 months in AP chem (i'm a instructor), as quickly as I forgot the - examine in front of the differential.

2016-10-18 04:32:02 · answer #2 · answered by ? 4 · 0 0

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