Proof by contradiction:
Assume that 5/sqrt(2) is a rational number. {We want to prove that this cannot happen by proving a contradiction.} Then 5/sqrt(2) can be expressed as a quotient of integers. That is,
5/sqrt(2) = m/n, for m and n having no common factors {If they did have a common factor, we can reduce the fraction, so let's assume this fraction is in its reduced form.}
Squaring both sides,
[5/sqrt(2)]^2 = (m^2)/(n^2)
25/2 = (m^2)/(n^2)
Multiply both sides by 2n^2,
25n^2 = 2m^2
This implies n^2 is even, which means n is even. Therefore,
n can be expressed in the form 2k, for some integer k. That is
n = 2k. Therefore,
25[2k]^2 = 2m^2
25[4k^2] = 2m^2
100k^2 = 2m^2. Dividing both sides by 2,
50k^2 = m^2. Factoring a 2 out on the left hand side,
2(25k^2) = m^2.
Since m^2 can be expressed as 2 times something, it follows that m^2 is an even number, which means m is an even number.
Therefore, m and n are both even numbers. This is a contradiction (since we stated at the start that m and n have no common factors).
Therefore, 5/sqrt(2) is an irrational number.
2007-03-11 23:50:10
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answer #1
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answered by Puggy 7
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The set of rational numbers is usually denoted by Mathematicians as script Q and is defined as the set of all numbers m/n where m is an integer and n is a nonzero integer.
some infinitely repeating numerals are not rational. others, like 1/3, 1.333333333... are; if they are rational, there will always be a repeating pattern resulting from the conversion of the divisor m (from n/m) to base 10.
I calculated your second example to rational expression. It's 406/900. Try it.
Here's how it's converted:
let m/n = 0.4511111...
m = .4511111... * n
100 m = 45.11111... *n
100 m = (45 + .111111...)*n
100m = 45n + n/9 # (1/9 = .11111...)
m = (45n + n/9)/100
use the value n(1) =9 to get a fractional m = 4.06;
multiply 4.06/9 by 100/100 to get the rational denotation.
you'll find the proof of the square root of 2 being non-rational here:
http://en.wikipedia.org/wiki/Irrational_number
from which it can be easily shown that 5/sqrt2 is also non-rational.
2007-03-12 06:45:19
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answer #2
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answered by kozzm0 7
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The proof that 5/sqrt2 is irrational would be similar to the proof that sqrt2 itself is irrational. This is proof by contradiction. You start by assuming that it is rational and equal to p/q in lowest terms. Then show that both p and q must be even numbers which contradicts previous statement. The only way to resolve this is to say that original assumption was incorrect.
2007-03-12 06:11:48
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answer #3
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answered by mathsmanretired 7
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sqrt2 is irrational since it is a non-terminating, non repeating decimal. you can not express it as a ration of two numbers. So any operation involving sqrt2 will give you result (if not zero) an irrational number.
0.451111... is a rational number.
you can express it as a ratio of two numbers:
ignore 0.45 in the calculation
a1 = 0.001
r=0.1
S = a1/(1-r)
S = 0.001/(1-0.1)
S = 0.001/0.9
S = 1/900
therefore, 0.451111...=45/100 + 1/900
= 406/900 ...a ratio
2007-03-12 06:25:13
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answer #4
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answered by datz 2
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5 / â2
= (â25) / (â2)
= â12.5
Since 12.5 is not a perfect square, so 5/â2 is not a rational number.
0.45111111111111111111111111111
= 203/450
Since it can be expressed as a fraction, it is a rational number.
2007-03-12 06:21:38
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answer #5
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answered by math freak 3
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any number with a denominator having a square root sign is irrational numbers.. all others are not. :)
Edited:
here's some more info from google;
http://www.homeschoolmath.net/teaching/proof_square_root_2_irrational.php
2007-03-12 06:07:23
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answer #6
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answered by shadcode 2
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x = .45111111111111111111111111111...
10x = 4.5111111111111111111111111111...
10x - x = 4.51 - .45
9x = 4.06
x = 203/450
2007-03-12 07:03:16
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answer #7
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answered by hbj 2
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x = .4511111111111111111111111111111111111
10x = 4.51111111111111111111111111111
10x - x = 4.51 - .45
9x = 4.06
x = 203/450
2007-03-12 06:08:00
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answer #8
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answered by ........ 5
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