X! = 362880 - and in gerneral?

Question

In general, is "X! = a number" solvable?
Or only with a table or trying?

The actual question why i asked is the following:

k!/(k+1) = "a number"

Is this solvable?

Answer 1

x! = (1)(2)(3)...(x)

362880 = (1)(2)(3)...(x)

x = 362880/[(1)(2)(3)(....]

you can use your calculator to be easy

362880/1 = 362880

362880/2 = 181440

181440/3 = 60480

60480/4 = 15120

15120/5 = 3024

3024/6 = 504

504/7 = 72

72/8 = 9

therefore: x! = 9! = 362880

Answer 2

Well, as many've answered, 362880 = 9!.
And in general, well, obviously only rare numbers are actually the factorial of something, but to solve - you just go and try to divide the given number by all you can, like 2, 3, 4, 5, 6, 7 etc, preferrably in the growing order. Well, if at a certain stage you get 1 - means you've found the answer. If you find another number, and can not perform the next division, means, the number is not a factorial. That's it.

Answer 3

"!" means the factorial of a number.

x! = x × (x-1) × (x-2) × ... × 2 × 1, where 0! = 1

so 9! = 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 362880

therefore x = 9.

To find the root of factorials, download this: http://www.geocities.com/tan_yi_kai1234567890/factorial.xls

Answer 4

Beware!!

9! = 362,880

(10! = 3,628,800)

I can't find any way to back calculate the factorial operator?

Answer 5

i dunno if there is a solution
i always tried..