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3 answers

I assume you want the maximum area possible with the length of fence given.

Length = 2x + t
160m = 2x + t
160m - 2x = t

Area = t * x (m²)
Area = (160 - 2x)x (m²)
Area = 160x - 2x² (m²)

For maximum area get the 1st derivative and let it be equal to zero.
δy/ δx of 160x - 2x²
δy/ δx = 160 - 4x
160 - 4x = 0
160 = 4x
x = 160 / 4
x = 40 m

Length = 160m = x + t + x
160m = 2x + t
160m = 2(40) + t
t = 80 m.

2007-03-11 22:13:40 · answer #1 · answered by Brenmore 5 · 0 0

I presume that you want maximum area. Use x for width of pen so length will be 160 - 2x. Write area as function of x and differentiate. Maximum area will occur when differential is zero.

2007-03-11 20:34:24 · answer #2 · answered by Anonymous · 1 0

The answr to eveything is 2.

2007-03-11 20:43:57 · answer #3 · answered by Mark B 1 · 0 1

finish the question please

2007-03-11 20:31:22 · answer #4 · answered by Bill F 6 · 0 0

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